Integrate Cos√x: Get Started Now!

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Homework Help Overview

The discussion revolves around the integration of the function cos(√x), focusing on the use of substitution and integration by parts. Participants are exploring the challenges associated with finding an appropriate substitution and managing the differential.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the substitution u = √x and its implications for the integral, questioning how to express dx in terms of du. There are attempts to clarify the relationship between the variables and the integral's form.

Discussion Status

Some participants have provided guidance on the substitution process and the resulting expressions, while others are still clarifying their understanding of the differential and integration steps. The conversation reflects a collaborative effort to navigate the problem without reaching a definitive conclusion.

Contextual Notes

It is noted that the integral is indefinite, and participants are working within the constraints of using substitution and integration by parts as specified in their homework guidelines.

EV33
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Integral of cos√x



We are supposed to use substitution and integration by parts but I really don't know where to even start.



No matter what I substitute for U I will be left without a du.
 
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what are your limits of integration?...what does your integral become when you use the substitution u=sqrt(x)? What is du?
 
There are no limits it is indefinite. If you let U= √x then du= 1/2√x and that is my problem because I am left with with integral of cos(u) and no du.
 
doesn't [itex]du=\frac{1}{2\sqrt{x}}dx[/itex] and doesn't that mean that [itex]dx=2 \sqrt{x} du= 2udu[/itex]?
 
Yes it does. So does that mean when I integrate I get u^2 sinu and from there I just need to back substitute?
 
Well, that means that

[itex]\int cos(\sqrt{x})dx= \int 2ucos(u)du[/itex]

now you'll need to integrate by-parts...try using f(u)=2u and g'(u)=cos(u)du
 
oh ok. Thank you for the help.
 

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