Integrate e^2x / SQRT (e^2x + 3)

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Homework Help Overview

The problem involves integrating the function e^2x divided by the square root of (e^2x + 3). The context is calculus, specifically focusing on integration techniques.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of substitution as a potential method, with one suggesting t = e^2x + 3. There is an exploration of how the integral transforms with this substitution, including the relationship between dt and e^2x.

Discussion Status

The discussion is ongoing, with participants providing guidance on the substitution method and clarifying the transformation of the integral. There is recognition of a mistake in the integration process, leading to further exploration of the correct approach.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the resources or methods they can use. There is an emphasis on understanding the reasoning behind the integration steps rather than simply arriving at a solution.

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Homework Statement



Integrate e^2x / SQRT [(e^2x) + 3)]

Homework Equations





The Attempt at a Solution



i know the solution, is: SQRT [(e^2x) + 3]

but i have no idea why. Please I need help

thank you
 
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Have you tried substitution?
 
eok20 said:
Have you tried substitution?

yes, t=e^2x + 3 but still nothing
 
Ok, if t=e^2x + 3 then dt = 2e^2x, and what does the integral become in terms of t and dt?
 
eok20 said:
Ok, if t=e^2x + 3 then dt = 2e^2x, and what does the integral become in terms of t and dt?

i have 1/2 (dt/ sqrt t)

so 1/2 t^(3/2) / (3/2)

then sqrt t / 3

then sqrt (e^2x+3)^3 / 3

its not the solution, it may be sqrt (e^2x+3)
 
Close, you have 1/2(dt/sqrt(t)) = 1/2 t^(-1/2) dt. You integrated 1/2 t^(1/2) dt instead
 
sqrt t is in the Denominator! So the power of t isn't 1/2, but actually... ?
 
eok20 said:
Close, you have 1/2(dt/sqrt(t)) = 1/2 t^(-1/2) dt. You integrated 1/2 t^(1/2) dt instead

its true! lol, it was my mistake, i forgot the change t^1/2 -> t^-1/2

thank you!
 

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