- #1

- 16

- 0

f(z) = 1/z and C = {z(t) = sin(t) + icos(t) | 0 <= t <= 2*pi}

I know f(z) = 1/r*e^(-it) = 1/r(cos(t) + isin(t)). But, when I try to take the contour integral by integrating f[z(t)]*z'(t), I get really messy formulas ((1/r*cos(sin(t)) + i*1/r*sin(cos(t)))*(cos(t) + -i*sin(t)), which makes me think I'm missing something.

Can anyone help me out on this? I have a midterm tomorrow and this was one of the practice questions.