How can I integrate x/(x^2 + ax + a^2)?

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SUMMARY

The integral of the function x/(x^2 + ax + a^2) can be effectively solved by completing the square in the denominator. Initial attempts using substitution methods, such as u=x^2, were unsuccessful. The discussion highlights that this integral will yield both a natural logarithm and an arctangent component. The key takeaway is that completing the square simplifies the integration process significantly.

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Hi. I want to integrate x/(x^2 + ax + a^2)
I tried substitution with u=x^2 then du =2x but that didn't work out neither did the substitution x^2 + ax
I thought of factorizing the denominator and using partial fractions, but I think that's not the way, can't figure out the factorization.
Could someone please give me a hint how to integrate this.
 
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If there was a 2ax in the denominator instead of ax, it would've been easier :smile:
This is a typical example of an integral which will have an ln-part and an arctan-part. Do you see why/how?
 
Swatch said:
Hi. I want to integrate x/(x^2 + ax + a^2)
I tried substitution with u=x^2 then du =2x but that didn't work out neither did the substitution x^2 + ax
I thought of factorizing the denominator and using partial fractions, but I think that's not the way, can't figure out the factorization.
Could someone please give me a hint how to integrate this.

TD's hint is best: complete the square!
 
Compleated the square and everything works. Thanks guys.
 

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