Conquering the Integral of (1/x)*exp(-ax^2): A Scientific Inquiry

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SUMMARY

The integral of (1/x)*exp(-ax^2) presents significant challenges, particularly due to the behavior of the function at zero and infinity. Users reported difficulties with Taylor expansion methods, leading to the conclusion that the expectation value is infinite. WolframAlpha provided a special function solution, indicating that traditional hand integration methods may not suffice for this problem. The discussion highlights the importance of recognizing the odd function properties in determining the integral's behavior.

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GrandsonOfMagnusCarl
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Homework Statement
Essentially - find <1/x>, i.e. the mean of 1/x. The distribution probability density is of the form exp(-ax^2).
Relevant Equations
Mean of G = integrate ( G f(x) ) dx
Hopeless. I tried to use Taylor expansion but the zeroes and infinities go out of control really quick.
I tried WolframAlpha and it gave a special function.
What integrating trick am I missing? Or is it nonsense to solve it simply by hand?
 
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The expectation value is infinite.
 
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Orodruin said:
The expectation value is infinite.
Ah I'm so stupid. Thank you. Also another reality check for me.
 
<1/x>=0 as 1/x is an odd function and G*f(x) is then also odd.
 

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