Integrating Absolute Value in Trigonometric Integrals

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SUMMARY

The integral \(\int \frac{dx}{\sin{x} |\sin{x}|}\) can be solved by recognizing that the absolute value can be expressed as the square root of a square. The definitive solution is \(-\frac{\cos{x} |\sin{x}|}{\sin^2{x}}\). To effectively tackle this integral, one must consider separate cases for when \(\sin{x} > 0\) and \(\sin{x} < 0\), which simplifies the integration process. This method of breaking down the integral based on the sign of the sine function is a standard approach when dealing with absolute values in integrals.

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Homework Statement



I need to solve the integral

[tex]\int \frac{dx}{\sin{x} |\sin{x}|}.[/tex]

Homework Equations



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The Attempt at a Solution



I know it's possible, the solution is [tex]-\frac{\cos{x} |\sin{x}|}{\sin^2{x}}[/tex], and I probably need to write the absolute as the square root of a square. I also probably need a substitution to simplify. I'm not having any luck finding such a substitution, however.
 
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Integrate it for sinx>0, then for sinx<0. Compare.
 
That worked perfectly. Thanks. I suppose that's the usual way to tackle an integral over an absolute value?
 

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