Integrating Acceleration to Find Velocity

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Homework Help Overview

The discussion revolves around integrating acceleration to find velocity in the context of a differential equation. The specific equation under consideration is the second-order differential equation relating acceleration to position, where acceleration is expressed as a function of position.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the integration of acceleration to derive velocity, with one suggesting the use of the Runge-Kutta method. There are questions about the feasibility of expressing velocity in a straightforward manner and the necessity of including additional variables in the system of equations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of how to approach the problem. Some guidance has been offered regarding the formulation of the equations, but there is no explicit consensus on the best method to proceed.

Contextual Notes

There is a mention of the challenge posed by the requirement of having two variables for the Runge-Kutta method, as the current formulation primarily involves one variable related to position.

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Homework Statement


I intend to use the Runge-Kutta method but to do so I need to be able to find the velocity [tex]\frac{dx(t)}{dt}[/tex] from the acceleration and I need some pointers on how to get that from the equation below. In other words I am having difficulty integrating the equation wrt time.


Homework Equations


[tex]\frac{d^{2}x(t)}{dt^{2}} = \frac{k}{x(t)^{2}}[/tex]

where k is a constant.


Any help would be appreciated. Thank-you.
 
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I don't think you can express the velocity in any easy form. Isn't the usual trick to add dx(t)/dt=v(t) to your list of equations and make the first equation dv(t)/dt=k/x(t)^2 and solve that first order system of equations with Runge-Kutta?
 
dont you need x(t)²??
 
Dick said:
I don't think you can express the velocity in any easy form. Isn't the usual trick to add dx(t)/dt=v(t) to your list of equations and make the first equation dv(t)/dt=k/x(t)^2 and solve that first order system of equations with Runge-Kutta?

The problem is Runge-Kutta method uses two variables, in my case x and t, though at the moment I only have 1 variable x as expressed in the equation of acceleration.
 

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