Integrating across circular surface

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SUMMARY

This discussion focuses on integrating across a circular surface in a Cartesian coordinate system defined by the center point (0, 0, L) and radius R. The original integral is expressed as \(\int_{0}^{\arctan(R/z_0)}{d\theta}\int_{0}^{2\pi}{d\phi}\). The user seeks to generalize this integral when integrating from a circle with radius R' (where R' < R) instead of the origin (0, 0, 0). The conversation highlights the need for clarity on the concept of "integrating from a circle."

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  • Understanding of multivariable calculus, specifically surface integrals.
  • Familiarity with Cartesian coordinate systems and spherical coordinates.
  • Knowledge of trigonometric functions, particularly arctangent.
  • Experience with mathematical notation and integral calculus.
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Students and professionals in mathematics, physics, and engineering who are working on problems involving surface integrals and circular geometries.

Niles
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Homework Statement


Hi

I am looking at a circle in a Cartesian coordinate system (x, y, z), with center at the point (0, 0, L) and radius R (so the z-axis is normal to the surface of the circle). From the origin (0, 0, 0), I would like to integrate across the circular surface, i.e.
<br /> \int_{0}^{\arctan(R/z_0)}{d\theta}\int_{0}^{2\pi}{d\phi}<br />

If I instead of integrating from a point at the origin now integrate from a circle with radius R'<R (also normal to the z-axis), how would the above integrals be generalized?
 
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Hi Niles! :smile:
Niles said:
If I … integrate from a circle …

Sorry, I don't understand what you mean by "integrate from a circle". :confused:
 

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