Integrating Double Integral of Cos(x+y) from 0 to pi: Step-by-Step Guide

  • Thread starter Thread starter Math10
  • Start date Start date
  • Tags Tags
    Integrate
Click For Summary

Homework Help Overview

The discussion revolves around integrating the double integral of cos(x+y) with respect to y and x, both ranging from 0 to pi. Participants are exploring the steps involved in evaluating this integral.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants present their attempts at integration, including a substitution method with u=x+y. There are questions about the correctness of the final steps and the application of trigonometric identities.

Discussion Status

The discussion is active, with participants questioning each other's reasoning and assumptions regarding trigonometric identities. Some guidance has been offered, but there is no explicit consensus on the correct approach yet.

Contextual Notes

There are indications of confusion regarding the application of the sine addition formula and the implications of integrating a zero function. Participants are also reiterating the original problem statement and the expected outcome.

Math10
Messages
301
Reaction score
0

Homework Statement


How to integrate the double integral cos(x+y) dy dx from 0 to pi and from 0 to pi again.

Homework Equations


The answer is -4.

The Attempt at a Solution


Here's the work:
u=x+y
du=dy
cos(u)du=sin(x+y)
integral of [sin(x+y)] evaluate from 0 to pi dx from 0 to pi
integral of (sin(x+pi)-sin(x))dx from 0 to pi
And what's next?
 
Physics news on Phys.org
Math10 said:

Homework Statement


How to integrate the double integral cos(x+y) dy dx from 0 to pi and from 0 to pi again.

Homework Equations


The answer is -4.

The Attempt at a Solution


Here's the work:
u=x+y
du=dy
cos(u)du=sin(x+y)
integral of [sin(x+y)] evaluate from 0 to pi dx from 0 to pi
integral of (sin(x+pi)-sin(x))dx from 0 to pi
And what's next?

Integrate again, similar to what you did for the first integral.
 
Er...doesn't the final step that you list give you the answer already?
 
But I can't. Because sin(x+pi)-sin(x)=sin(x)+sin(pi)-sin(x)=sin(pi)=0. The integral of 0 is?
 
Math10 said:
But I can't. Because sin(x+pi)-sin(x)=sin(x)+sin(pi)-sin(x)=sin(pi)=0. The integral of 0 is?
##\sin(a+b)\ne \sin a +\sin b##
 
Math10 said:
Because sin(x+pi)=sin(x)+sin(pi)
That is most certainly not correct. Can you check your compound angle formula?
 
Then what's sin(a+b)?
 
@Fightfish , thank you so much for the info! I got it!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
2K