Integrating $\frac{x}{1 + \sin(x) \cos(x)}$ from 0 to $\pi$

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Homework Help Overview

The discussion revolves around the integral of the function $\frac{x}{1 + \sin(x) \cos(x)}$ from 0 to $\pi$. Participants are exploring the complexities of this integral within the context of calculus.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants question why the integral is considered difficult and request the original poster to share their work. There are inquiries about the methods that could be employed to tackle the integral, including suggestions related to trigonometric identities.

Discussion Status

Some participants emphasize the importance of guiding the original poster through their thought process rather than providing direct answers. There is a focus on teaching and understanding rather than competition, with a consensus on maintaining the integrity of the homework help context.

Contextual Notes

There is an acknowledgment that the integral is likely part of a homework assignment, and participants are cautious about providing direct solutions to avoid undermining the learning process.

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[tex] \int_0^{\pi} \frac{x}{1+\sin(x)\cos(x)} dx[/tex]
 
Last edited:
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how does latex in this forum works? how to get rid of the 18416 ?

testing

[tex]\frac{1}{2}[/tex]

[tex]\int_0^{\pi} \frac{x}{1+\sin(x)\cos(x)} dx[/tex]
 
Why is this a hard integral? Post your work please
 
what is the method used?
 
This is not a competition. I had the answer the minute I looked at the problem to make sure it existed. The point is to teach him how to find the solution by looking at his attempt at the solution. Please don't randomly post an answer which does not help him in any way.


To OP: for what its worth, sin(2*x) = 2*sin(x)*cos(x). You can try u=2*x, du = 2 dx
 
Last edited:
cronxeh said:
This is not a competition. I had the answer the minute I looked at the problem to make sure it existed. The point is to teach him how to find the solution by looking at his attempt at the solution. Please don't randomly post an answer which does not help him in any way.

Exactly. I've deleted the posts with answers in them. This is most likely homework, so giving the OP the answer is cheating. I'm moving this thread to Homework Help, Calculus and Beyond.
 

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