Integrating rational functions

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Partial fraction decomposition is essential for integrating rational functions, as all such functions can be integrated using known methods after decomposition. The challenge arises with irreducible quadratic factors in the denominator, which require a specific form for integration. The integration of terms like (ax+b)/qm can be simplified through strategic manipulation, such as adding and subtracting constants for u-substitution. Despite the book's claim that certain forms are integrable, users often struggle with cases like c/qm when m is a natural number. Techniques like completing the square or trigonometric substitution can effectively address these integration challenges.
suffian
I've just finished reading the section on partial fraction integration from my text. The book describes how all rational functions can be integrated by performing a partial fraction decomposition and subsequently integrating the partial fractions using methods that are already known. I tried to verify this fact for myself, but I ran into some trouble with irreducible quadratic factors occurring in the denominator of the rational function (the linear factors look like they could all just be "ln-ified").

As shown in the text, an irreducible quadratic factor q = dx2 + ex + f raised to n in the denominator of a rational function needs to be taken apart as follows:
(a1x+b1)/q + (a2x+b2)/q2 + ... + (an-1x+bn-1)/qn-1 + (anx+bn)/qn

So the problem of integrating all rational functions relegates to solving integrals of the following form:
(ax+b)/qm (m is natural number)

With a little insight, you can reduce this a little further by adding and subtracing a constant to make it partially amenable to a u-substitution:
(ax+b +c -c)/qm (c such that ax+b+c is k*q')
(ax+b+c)/qm - c/qm (where left integral can be solved with u-sub)

I don't see how to reduce this last form (c/qm where c constant and q quadratic) despite the claim by the book that it is integrable using methods already known. Does anyone else know (or can figure out) how it's possible to integrate this form in the general case?
 
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Although m must be an integer in your problem, consider how you would integrate 1/q^(1/2).

The next post is another hint, but try going by just this one if you can!
 
Complete the square, trig substitution.
 
yeah, that seems to work well enough. it was actually just the next section, but thanks a lot.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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