Integrating sqrt(3-x²)/sqrt(3) and sqrt(3-3x²)

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ACLerok
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how do i integrate sqrt(3-(x^2))/sqrt(3)? i put the sqrt(3) outside the integral and tried using the substitution method to integrate it but there is still an x in there?

same thing with integrating sqrt(3-3*(x^2))

Thanks! This thing is due tomorrow.. :eek:
 
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that's a classic trig substitution case. (Use sine trig substitution).
 
vsage said:
that's a classic trig substitution case. (Use sine trig substitution).

both of them?
 
Yeah it's not that much different with both.. just different coefficients you have to pull out of the square root.
 
alright i think i almost got it.. now i have another question, what's the integral of cos^2(x)?
 
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You've got the identity:
[tex]\cos^{2}x=\frac{1+\cos2x}{2}[/tex]