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## Homework Statement

[tex]\int\sqrt{2*x-1}[/tex]

## Homework Equations

## The Attempt at a Solution

## Homework Statement

Obviously this can be fixed with the antiderivative of a linear function with proper constants i.e. [tex]\int A\times f(bx + c) = \frac{A}{b} F(bx + c)[/tex], however my instructor provided me with a "clue" which I somehow cant seem to work out.

He claims that [tex]\int\sqrt{2*x-1}[/tex] is equivilant to [tex]\int u^2[/tex] using "the right" substitution. My idea usually is:

1) [tex]u = \sqrt{2*x - 1}[/tex]

2) [tex]x = u^2 [/tex]

3) [tex]dx = 2u du[/tex]

Which would lead to [tex]\int u dx = \int u 2u du = \int 2u^2 du[/tex].

Obviously this is NOT identical to what he suggests, so can anyone point me in the right direction? I'm quite keen to know how he see such a problem.