Integrating Trigonometric Functions: How to Remember and Use Identities?

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Homework Statement


I have a problem in part b
Printed textbook problem 10: a uniform chain hangs in the shape of the catenary y = cosh x between x = -1 and x = 1. Find (a) its length, (b) y-bar, with part (b) circled.


Homework Equations





The Attempt at a Solution


How to integral the function?

Handwritten derivation on lined paper: arc length l = integral of ds, reduced to integral from -1 to 1 of cosh x dx giving 2 sinh 1, then part (b) integral of y-bar rho ds = integral of y rho ds leading to integral from -1 to 1 of cos^2 hx dx.
 
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  • Handwritten calculus working on lined paper: arc length l = integral of ds, reduced to integral from -1 to 1 of cosh x dx giving 2 sinh 1; part b sets l times y-bar equal to integral of y rho ds, leading to integral from -1 to 1 of cos^2 h x dx.
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  • Printed textbook problem 10: a uniform chain hangs in the shape of the catenary y = cosh x between x = -1 and x = 1. Find (a) its length, (b) y-bar, with (b) circled.
    3.jpg
    6.5 KB · Views: 594
  • Handwritten derivation of an arc length integral: l = integral of ds equals integral from 0 to 2 of the square root of (1 + 1/(4x)) dx, then a limit as a approaches infinity of the integral from a to sqrt(8/3) of u^2 over 2(u^2 - 1)^2 du, with substitution u = sqrt(1 + 1/(4x)), x = 1/(4(u^2 - 1)), and dx = -u/(2(u^2 - 1)^2) du.
    4.jpg
    24.3 KB · Views: 579
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1. Homework Statement
I would like to ask for 18 and20

Printed textbook page listing calculus problems 17 to 31 about the curve y = sqrt(x) between x = 0 and x = 2, with problems 18 and 20 circled.



2. Homework Equations



3. The Attempt at a Solution
Again how to integral the function?

Handwritten calculus working on lined paper: arc length l = integral of ds, equal to the integral from 0 to 2 of the square root of 1 + 1/(4x) dx, then a limit as a tends to infinity of the integral from a to root 8 of u^2 over 2(u^2-1)^2 du, with the substitution u = root(1 + 1/(4x)) and its derivatives beside it.


Handwritten surface area setup on lined paper labelled 20: S = integral from 0 to 2 of 2πy ds, then 2π times integral from 0 to 2 of sqrt(x) sqrt(1 + 1/(4x)) dx, then 2π times integral from 0 to 2 of sqrt(x + 1/4) dx.
 
Attachments
  • Printed textbook page listing calculus problems 17 to 31 about the curve y = sqrt(x) between x = 0 and x = 2, with problems 18 and 20 circled.
    5.jpg
    64.3 KB · Views: 596
  • Handwritten surface area setup: S = integral from 0 to 2 of 2πy ds, then 2π times integral from 0 to 2 of sqrt(x) sqrt(1 + 1/(4x)) dx, then 2π times integral from 0 to 2 of sqrt(x + 1/4) dx.
    6.jpg
    28.2 KB · Views: 626
10a looks fine.

For 10b, take advantage of the following trig identity:

cosh2 x = [1 + cosh (2x)]/2
 
gb7nash said:
10a looks fine.

For 10b, take advantage of the following trig identity:

cosh2 x = [1 + cosh (2x)]/2

Oh no, I know this identity, but there are too many identity and formula so I can't remember it before you tell me. How can I make sure that I remember all of them? Or where can I check these useful identity?
 
http://planetmath.org/encyclopedia/HyperbolicIdentities.html

As far as knowing which ones to remember, it would depend on what you're trying to do and what class you're in. For a lot of integral problems, the identities I usually see are sin2 + cos2 = 1 (and any other pythagorean identities), and half/double angle formulas.
 
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gb7nash said:
http://planetmath.org/encyclopedia/HyperbolicIdentities.html

As far as knowing which ones to remember, it would depend on what you're trying to do and what class you're in. For a lot of integral problems, the identities I usually see are sin2 + cos2 = 1 (and any other pythagorean identities), and half/double angle formulas.

Thanks so much.
Shall we move on #2?
I just have some problems.
 
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