Integrating with volume element (d^3)x

Click For Summary
The discussion focuses on integrating a specific function involving a volume element in three dimensions, specifically the integral of (d^3)k exp[ik*(x1-x2)]/[(k^2+m^2)(2pi)^3]. Participants clarify that d^3x represents a volume integral with differential elements dx, dy, dz, while d^3k denotes dk_x dk_y dk_z, the components of the k vector. The integral is related to the energy equation that leads to the inverse square law (1/r^2). The conversation emphasizes the importance of understanding the notation and the context of the integration in Cartesian coordinates. Overall, the thread seeks guidance on evaluating this complex integral.
captain
Messages
163
Reaction score
0
i'm at a loss about how to do this type of integration. can some one show me how to evaluate the integral of (d^3)k exp[ik*(x1-x2)]/[(k^2+m^2)(2pi)^3], where "*" is the dot product between the 3 vector k and (x1-x2), which are both 3 vectors. this come from the energy equation used to get the inverse square law (1/r^2).
 
Physics news on Phys.org
The notation d^3x is usually shorthand for a volume integral with differential elements dx, dy, dz (In Cartesian coordinates.) So:

\int_V f(x,y,z) d^3x = \int\int\int f(x,y,z) dxdydz

So, in your case, d^3k probably stands for dk_x dk_y dk_z, where k_x, etc. are the components of the k vector. (Again, in Cartesian Coordinates)
 

Similar threads

Replies
4
Views
2K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
996
  • · Replies 9 ·
Replies
9
Views
1K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K