1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Integrating with volume element (d^3)x

  1. Aug 12, 2007 #1
    i'm at a loss about how to do this type of integration. can some one show me how to evaluate the integral of (d^3)k exp[ik*(x1-x2)]/[(k^2+m^2)(2pi)^3], where "*" is the dot product between the 3 vector k and (x1-x2), which are both 3 vectors. this come from the energy equation used to get the inverse square law (1/r^2).
     
  2. jcsd
  3. Aug 12, 2007 #2

    G01

    User Avatar
    Homework Helper
    Gold Member

    The notation d^3x is usually shorthand for a volume integral with differential elements dx, dy, dz (In Cartesian coordinates.) So:

    [tex]\int_V f(x,y,z) d^3x = \int\int\int f(x,y,z) dxdydz [/tex]

    So, in your case, [tex]d^3k[/tex] probably stands for [tex]dk_x dk_y dk_z[/tex], where k_x, etc. are the components of the k vector. (Again, in Cartesian Coordinates)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Integrating with volume element (d^3)x
  1. 3-D Statics Problem (Replies: 2)

  2. 3 D space (Replies: 3)

Loading...