Integrating with volume element (d^3)x

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SUMMARY

The discussion focuses on evaluating the integral of the function (d^3)k exp[ik*(x1-x2)]/[(k^2+m^2)(2pi)^3], which is derived from energy equations related to the inverse square law (1/r^2). The notation d^3x represents a volume integral in Cartesian coordinates, specifically expressed as ∫∫∫ f(x,y,z) dxdydz. Additionally, d^3k denotes the differential volume element in k-space, represented as dk_x dk_y dk_z, where k_x, k_y, and k_z are the components of the vector k.

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i'm at a loss about how to do this type of integration. can some one show me how to evaluate the integral of (d^3)k exp[ik*(x1-x2)]/[(k^2+m^2)(2pi)^3], where "*" is the dot product between the 3 vector k and (x1-x2), which are both 3 vectors. this come from the energy equation used to get the inverse square law (1/r^2).
 
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The notation d^3x is usually shorthand for a volume integral with differential elements dx, dy, dz (In Cartesian coordinates.) So:

\int_V f(x,y,z) d^3x = \int\int\int f(x,y,z) dxdydz

So, in your case, d^3k probably stands for dk_x dk_y dk_z, where k_x, etc. are the components of the k vector. (Again, in Cartesian Coordinates)
 

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