Integration by Parts: Evaluating e^xcos3x dx & x^2/(2(1+x^2))

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SUMMARY

The discussion focuses on evaluating the integral of (e^x)cos3x dx using integration by parts, with the expected result being (e^x/10)*(cos3x + 3sin3x). The user initially set u=cos3x and dv/dx=e^x but struggled with the anti-differentiation process, leading to incorrect results. Additionally, the user sought assistance with the integral of (x^2)/(2(1+x^2)), receiving advice to manipulate the integral by splitting and simplifying it for easier evaluation.

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Homework Statement


Hi, I'm trying to evaluate the integration of (e^x)cos3x dx, by using integration by parts. I've already done a couple of similar questions on integration by parts but this one seems to puzzle me.


Homework Equations


The answer is supposed to be (e^x/10)*(cos3x + 3sin3x), I can't seem to get to it.


The Attempt at a Solution


I've basically taken the same approach to this question as the other couple of integration by parts questions I've done but the answer is never right. I let u=cos3x and dv/dx=e^x. And basically just subbed back into the formula uv - integ.v*(du/dx).
I suspect I may be anti-differentiating the second part wrong, which I think is (e^x)*3sin3x. I get 3e^x(3cos3x+sin3x). Any idea where I went wrong?

I'm also having trouble finding the integral of (x^2)/[2(1+x^2)]. Any advice or help would be appreciated. Thanks in advance.
 
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Integration by parts is so much fun tht you should do it twice.

At least in this case you should.
 
On the integration by parts after you integrate twice by parts look on the left and right side of the equation and see if you see anything common like:

x= y+ 3x
just imagine that x is the original integral, when you get like terms on the right side, you can manipulate the integral to get left equal right. I hope you can see what I am saying.

On the second integral, divide and split the integral and see if it would make it easier for you to integrate
 
Last edited:
Yup On the second one, Add 1 and minus 1 from the numerator. Don't think its stupid, just do it! And take the factor of 1/2 out of the integral.
 
Oh I see. I get everything now, thanks a bunch guys. Very appreciated.
 

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