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## Homework Statement

|x

^{3}sqrt(4-x

^{2})dx

## Homework Equations

uv - | vdu

## The Attempt at a Solution

u = x

^{2}v = -1/3(4-x

^{2})

^{3/2}

du = -2xdx dv = x(4-x

^{2})

^{1/2}

uv - | vdu

x

^{2}(1/3)(4-x

^{2})

^{3/2}- | 1/3(4-x

^{2})

^{3/2}(2xdx)

x

^{2}(1/3)(4-x

^{2})

^{3/2}+(1/3)|(4-x

^{2})

^{3/2}(2xdx)

u = 4 - x

^{2}

du = -2xdx

x

^{2}(1/3)(4-x

^{2})

^{3/2}- (1/3)| u

^{3/2}du

x

^{2}(1/3)(4-x

^{2})

^{3/2}-(1/3)2/5u

^{5/2}

x

^{2}(1/3)(4-x

^{2})

^{3/2}-(1/3)(2/5)(4-x

^{2})

^{5/2}

x

^{2}-(1/3)(4-x

^{2})

^{3/2}-(2/15)(4-x

^{2})

^{5/2}

Is this all I need? The answer I was supposed to get is -1/15(4-x

^{2})

^{3/2}(8+3x

^{2}) I guess I dont see how that correlates

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