Integration by Parts with Domain Warning

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SUMMARY

The discussion focuses on the integration of the function $\int x\ \cot^2\left({x}\right) dx$ using integration by parts. The participants confirm the choice of $u=x$ and $dv=\cot^2\left({x}\right) dx$, leading to the calculation of $du=dx$ and the integration of $dv$ resulting in $v=-\frac{\cos\left({x}\right)+x\sin\left({x}\right)}{\sin\left({x}\right)}$. A domain warning was encountered during the process, indicating potential issues with the function's domain when evaluated on a TI calculator.

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with trigonometric identities, particularly $\cot(x)$ and $\csc(x)$.
  • Basic knowledge of calculus, including differentiation and integration of functions.
  • Experience with using graphing calculators, such as TI calculators, for symbolic computation.
NEXT STEPS
  • Study the integration by parts formula and its applications in calculus.
  • Learn about the implications of domain warnings in calculus, especially in relation to trigonometric functions.
  • Explore the derivation and properties of trigonometric identities, particularly $\cot^2(x)$ and $\csc^2(x)$.
  • Practice using TI calculators for symbolic integration and understand how to interpret their outputs.
USEFUL FOR

Students and educators in calculus, mathematicians dealing with integration techniques, and anyone using TI calculators for advanced mathematical computations.

karush
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$\int x\ \cot^2\left({x}\right) dx $
$u=x$ $dv=\cot^2\left({x}\right) dx $
$du=\frac{x^2}{2}$ $v=\frac{-\cos\left({x}\right)+x\sin\left({x}\right)}{\sin\left({x}\right)}$
 
Last edited:
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Hi karush,

Could you show your workings for $v$?
We have $dv=\cot^2\left({x}\right) dx$
$v=\int (\csc^2 x -1) \,dx$

Can you proceed?
 
I agree with you choice of $u$ and $dv$:

$$u=x\,\therefore\,du=dx$$ (You integrated rather than differentiated)

$$dv=\cot^2(x)\,dx=\left(\csc^2(x)-1\right)\,dx\,\therefore\,v=?$$
 
That what I got for $v$ with the TI ??
 
karush said:
That what I got for $v$ with the TI ??

I suspect your TI spat out:

$$v=-\frac{\cos\left({x}\right)+x\sin\left({x}\right)}{\sin\left({x}\right)}$$ :D
 
$uv-\int\ v\ du$

$-x(\cot\left({x}\right)-x)+\int \cot\left({x}\right)dx -\int x\ dx$

My TI returned a domain warning??
 

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