Integration by Parts: x^2(2+x^3)^4, x(x^2+2)^5, xcosx

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Homework Help Overview

The discussion revolves around integrating three functions: \(x^2(2+x^3)^4\), \(x(x^2+2)^5\), and \(x\cos x\). Participants are exploring methods such as substitution and integration by parts to solve these integrals.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants present their attempts at integrating the functions, using substitution and integration by parts. Some question the correctness of the steps taken, particularly regarding the first integral, and suggest verifying results through expansion or alternative methods.

Discussion Status

There is ongoing dialogue about the correctness of the integration steps. Some participants express a desire for confirmation of their methods, while others suggest re-evaluating the first integral specifically. A few participants note that certain approaches may need to be redone for clarity.

Contextual Notes

Participants mention constraints regarding the use of re-calculations in responses, indicating a focus on understanding the steps rather than simply providing answers.

pinnacleprouk
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Could you please confirm my answers as correct or incorrect, if incorrect please point out errors and assist in correcting errors.

Thanks in advance

Homework Statement



Intergrate the following functions with respect to x using recognition, substitution or intergration by parts:

x^2(2+x^3)^4

x(x^2+2)^5

xcosx

The Attempt at a Solution



1)
integral(x^2(2+x^3)^4)
put (2+x^3) =x
thus
3x^2dx = dz
or
x^2dx = dz/3

the integral becomes
integral(z^4dz)/3
= z^5/15
=(2+x^3)^5/15 + c

2)
integral(x(x^2+2)^5)
put x^2+2=z
or
2xdx = dz
thus
xdx = dz/2
integral(z^5/2)dz
= z^6/12+c
=(x^2+2)^6/12 + c

3) integral(xcosx)
x(sinx) - integral(sinx)
= -xsinx+cosx +c
 
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pinnacleprouk said:
Could you please confirm my answers as correct or incorrect, if incorrect please point out errors and assist in correcting errors.

Thanks in advance


Homework Statement



Intergrate the following functions with respect to x using recognition, substitution or intergration by parts:

x^2(2+x^3)^4

x(x^2+2)^5

xcosx


The Attempt at a Solution



1)
integral(x^2(2+x^3)^4)
put (2+x^3) =x
thus
3x^2dx = dz
or
x^2dx = dz/3

the integral becomes
integral(z^4dz)/3
= z^5/15
=(2+x^3)^5/15 + c

2)
integral(x(x^2+2)^5)
put x^2+2=z
or
2xdx = dz
thus
xdx = dz/2
integral(z^5/2)dz
= z^6/12+c
=(x^2+2)^6/12 + c

3) integral(xcosx)
x(sinx) - integral(sinx)
= -xsinx+cosx +c

You can test your final result using either mathematical software like Maple, Mathematica and or google Wolfram integrator it using the integration engine of Mathematica.
 
while I appreciate your reply, I would rather ask here to see if the steps taken are correct as well as the final result!

Thanks
 
pinnacleprouk said:
1)
integral(x^2(2+x^3)^4)
put (2+x^3) =x
thus...

I think you mean (2+x^3) = z

Last one is definitely correct and, albeit a little tedious, the other 2 can easily be confirmed by expanding the brackets and integrating directly.
 
pinnacleprouk said:
while I appreciate your reply, I would rather ask here to see if the steps taken are correct as well as the final result!

Thanks

Okay, but as you know which I learned yesterday its forbidden to reply with re-calculations to you.

2) and 3) are correct but you need to redo 1) using integration by parts and integration by substitution!
 

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