Integration - Determine Maximum height - HELP

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Homework Help Overview

The problem involves determining the maximum height of a baseball thrown upward from a height of 2 meters with an initial velocity of 10 meters per second. The context includes both calculus and physics principles, particularly focusing on integration and energy conservation.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using calculus to find the maximum height through integration, while others suggest considering energy conservation principles. There is a question about how to apply the equations of motion to find the maximum height, and some participants express confusion regarding the appropriate units and methods to use.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem. Some guidance has been offered regarding energy conservation, while others emphasize the need to adhere to the correct units in calculations. There is no explicit consensus on the method to be used.

Contextual Notes

Participants note the importance of using metric units for the calculations, as the problem is stated in those terms. There is also mention of the need to clarify the equations of motion and their applicability in this context.

ayrestaurant
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Homework Statement




A baseball is thrown upward from a height of 2m with an initial velocity of 10m/s. Determine its maximum height.



Homework Equations



S(0) = 2m
S'(0) = 10m/s

The Attempt at a Solution





S'(t) = -32t + 10
S(t) = -16t^2 + 10t + 2

I know that if you equal s(t) = 0 you get time, but how do I get maximum height?

Thanx in advanced!
 
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ayrestaurant said:

Homework Statement




A baseball is thrown upward from a height of 2m with an initial velocity of 10m/s. Determine its maximum height.



Homework Equations



S(0) = 2m
S'(0) = 10m/s

The Attempt at a Solution





S'(t) = -32t + 10
S(t) = -16t^2 + 10t + 2

I know that if you equal s(t) = 0 you get time, but how do I get maximum height?

Thanx in advanced!

The easiest way would be to use energy conservation. Are you familiar with the equation:

TE = PE + KE (total energy is equal to potential energy plus kinetic energy)

What is the KE at the top of the object's travel?
 
berkeman said:
The easiest way would be to use energy conservation. Are you familiar with the equation:

TE = PE + KE (total energy is equal to potential energy plus kinetic energy)

What is the KE at the top of the object's travel?

hey thanx!

yepp.. in fact its better using physics, but its calculus; I have to use the integration method
 
btw ... the answer is 7.1m... i just don't know how to get there
 
ayrestaurant:

You should read your original problem again more carefully.

The distances, velocities, etc. are given in the metric system.

If you use formulas derived for Imperial units, you will never solve this problem.

If the acceleration due to gravity is 32.2 fps2 in Imperial units, what is the equivalent acceleration in m/s2?
 

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