# Integration - Determine Maximum height - HELP!

## Homework Statement

A baseball is thrown upward from a height of 2m with an initial velocity of 10m/s. Determine its maximum height.

S(0) = 2m
S'(0) = 10m/s

## The Attempt at a Solution

S'(t) = -32t + 10
S(t) = -16t^2 + 10t + 2

I know that if you equal s(t) = 0 you get time, but how do I get maximum height?

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berkeman
Mentor

## Homework Statement

A baseball is thrown upward from a height of 2m with an initial velocity of 10m/s. Determine its maximum height.

S(0) = 2m
S'(0) = 10m/s

## The Attempt at a Solution

S'(t) = -32t + 10
S(t) = -16t^2 + 10t + 2

I know that if you equal s(t) = 0 you get time, but how do I get maximum height?

The easiest way would be to use energy conservation. Are you familiar with the equation:

TE = PE + KE (total energy is equal to potential energy plus kinetic energy)

What is the KE at the top of the object's travel?

The easiest way would be to use energy conservation. Are you familiar with the equation:

TE = PE + KE (total energy is equal to potential energy plus kinetic energy)

What is the KE at the top of the object's travel?
hey thanx!

yepp.. in fact its better using physics, but its calculus; I have to use the integration method

btw ... the answer is 7.1m... i just dont know how to get there

SteamKing
Staff Emeritus
Homework Helper
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