Integration involving a physics problem.

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SUMMARY

This discussion focuses on solving a physics problem related to the electric field generated by a uniformly charged line segment along the y-axis. The user is tasked with integrating the expression for the electric field at a point on the x-axis, specifically using the formula for electric field strength, E = kQ/r². The integration involves evaluating the integral (kQ/2a)∫(x dy)/(x² + y²)^(3/2), which the user finds challenging. Suggestions include utilizing integral tables and considering trigonometric substitution to simplify the integration process.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of trigonometric identities and substitutions
  • Experience with integral tables and their applications
NEXT STEPS
  • Study trigonometric substitution methods in calculus
  • Learn how to use integral tables effectively for physics problems
  • Practice integration of functions involving multiple variables
  • Explore online tools like Wolfram Alpha for checking integration solutions
USEFUL FOR

Students in physics or engineering courses, particularly those tackling electromagnetism and calculus integration problems, will benefit from this discussion.

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Homework Statement


Hello all! I'm currently trying to work a problem for my Physics 2 class (for engineering and science majors). The example problem deals with "Field of a charged line segment." I conceptually understand the problem, but I am having trouble with the details involving the integration.

The problem: "Positive charge Q is distributed uniformly along the y-axis between y= -a and y= +a. Find the electric field at point P on the x-axis at a distance x from the origin."

I know that [itex]\stackrel{\rightarrow}{E}[/itex]= [itex]\frac{kQ}{r^{2}}[/itex]

λ=[itex]\frac{Q}{2a}[/itex]

dQ=λdy=[itex]\frac{Q}{2a}[/itex]dy

r=[itex]\sqrt{x^{2}+y^{2}}[/itex]

therfore; dE=(k)([itex]\frac{dQ}{r^{2}}[/itex])= (k)([itex]\frac{Q}{2a}[/itex])([itex]\frac{dy}{x^{2}+y^{2}}[/itex])

E[itex]_{y}=[/itex][itex]_{-a}[/itex]∫[itex]^{+a}[/itex]dE[itex]_{y}[/itex]=0

E[itex]_{x}=[/itex][itex]_{-a}[/itex]∫[itex]^{+a}[/itex]dE[itex]_{x}[/itex]=[itex]_{-a}[/itex]∫[itex]^{+a}[/itex](k)([itex]\frac{Q}{2a}[/itex])([itex]\frac{dy}{x^{2}+y^{2}}[/itex])(cosθ)

cosθ=[itex]\frac{x}{\sqrt{x^{2}+y^{2}}}[/itex]

E[itex]_{x}=[/itex][itex]_{-a}[/itex]∫[itex]^{+a}[/itex]dE[itex]_{x}[/itex]=[itex]_{-a}[/itex]∫[itex]^{+a}[/itex](k)([itex]\frac{Q}{2a}[/itex])([itex]\frac{dy}{x^{2}+y^{2}}[/itex])([itex]\frac{x}{\sqrt{x^{2}+y^{2}}}[/itex])

simplifying and factoring out constants gives:

([itex]\frac{kQ}{2a}[/itex])[itex]_{-a}[/itex]∫[itex]^{+a}[/itex][itex]\frac{xdy}{(x^{2}+y^{2})^{3/2}}[/itex]

Here is where my problem comes in... I don't know how to integrate this. The book says "a table of integrals will help."

The solution is given to be:

E[itex]_{x}[/itex]=[itex]\frac{kQ}{x\sqrt{x^{2}+y^{2}}}[/itex]



Homework Equations





The Attempt at a Solution



I do have the latest CRC book which has integral tables in it. I looked at the general forms containing: c2+x2. The one it looked the closest to was: [itex]\frac{dx}{(c^{2}+x^{2})^{n}}[/itex]. But I'm not sure... I believe the x's may be treated as constants since I'm integrating with respect to y, but I'm not exactly sure how to go about working it. I looked a U-substitution but I get bogged down and confused by the fact that I am integrating a function that includes two variables. Any help would greatly be appreciated. Again, I understand the concept, but I'm getting confused on the calculus part of it (the integration/last step). Thank you.
 
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It looks like a trig substitution might work. Try ##y = x\tan\theta,\, dy=x\sec^2\theta\,d\theta,\,
\sqrt{x^2+y^2}=x\sec\theta## and see if that does anything for you.
 

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