1. The problem statement, all variables and given/known data Evaluate the integral when x > 0: indefinite integral of ln(x2+19x+84)dx 2. Relevant equations I know I need to use some form of integration by parts: integral of u*dv=uv-(integral of(du*v)) 3. The attempt at a solution I began by making u=ln(x2+19x+84) and dv=dx. Thus, (after u-substitution) du=(2x+19)/(x2+19x+84) and v=x. After putting that in the formula, we get x*ln(x2+19x+84)-(integral of)((2x2+19x)/(x2+19x+84)). After simplifying that, I get: x*ln(x2+19x+84)-((x2+19x+84)(4x+19)-(2x2+19x)(2x+19))/((x2+19x+84)2) But according to the program I am using, that is the incorrect answer. Do you have any suggestions? Thanks.