1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Integration of an inverse function

  1. Jan 8, 2009 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    3. The attempt at a solution

    I can get to s certain point and I know I need to do substitution but, everytime I try a substitution it just creates a more difficult problem.


    I've tried substitution x^-1 for U and using (x+3)^-1 for dv but, none of it works. If someone could give me a gentle nudge it would be appreciated.

  2. jcsd
  3. Jan 8, 2009 #2


    User Avatar
    Homework Helper
    Gold Member

    This problem is an ideal candidate for the method of "partial fractions".

    Try decomposing [tex]\frac{1}{x(x+3)}[/tex] into the form [tex]\frac{A}{x}+\frac{B}{x+3}[/tex] where A and B are constants you need to determine.
  4. Jan 8, 2009 #3
    OH man so obvious. Your the man thank you so much. I havn't had a math class in over a year and now I'm taking diff eq. Bad idea you should definetly keep them all together.
  5. Jan 8, 2009 #4


    User Avatar
    Staff Emeritus
    Science Advisor

    And, when talking about functions, be careful to distinguish between "reciprocal" and "inverse" functions!
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Integration of an inverse function