- #1

- 24

- 0

## Homework Statement

∫ [(x + 2)(x - 2)] / (x - 2) dx from -3 to 3

## Homework Equations

## The Attempt at a Solution

∫ [(x + 2)(x - 2)] / (x - 2) dx from -3 to 3

= [ (x^2)/2 + 2x ] from -3 to 3

I know that this function is integrable, but I could not apply the 2nd part of fundamental theorem of calculus since the function has a removable discontinuity at x=2. So how do I proceed?