(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

∫ [(x + 2)(x - 2)] / (x - 2) dx from -3 to 3

2. Relevant equations

3. The attempt at a solution

∫ [(x + 2)(x - 2)] / (x - 2) dx from -3 to 3

= [ (x^2)/2 + 2x ] from -3 to 3

I know that this function is integrable, but I could not apply the 2nd part of fundamental theorem of calculus since the function has a removable discontinuity at x=2. So how do I proceed?

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# Homework Help: Integration of discontinuous function

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