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Integration of Inverse Tangent Function

  1. Oct 28, 2007 #1
    [SOLVED] Integration of Inverse Tangent Function

    [tex]\int \frac{e^{x}}{4+9e^{2x}}dx[/tex]

    Saw the problem, looked at it for a bit. Noticed that it is a inverse Tangent function. Played with some integration by parts and substitution and couldn't figure it out. Can anybody toss me a starting point on this problem?

  2. jcsd
  3. Oct 28, 2007 #2
    Think of 9e^(2x) as (3e^x)^2, that should get you started.
  4. Oct 28, 2007 #3
    you're aim should be to put your integral in this form [tex]\int\frac{1}{a^{2}+x^{2}}dx[/tex] so algebraically manipulate it as hotcommodity suggested.
  5. Oct 28, 2007 #4
    Ahh....thank you guys =P

    For some reason I wasn't letting myself put the 9e^2x as (3e^x)^2. Basic order of operations tricks me again.
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