Integration of velocity to get displacement

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To find the displacement of a particle moving along the positive x-axis with velocity v = α√x, the correct approach is to integrate velocity with respect to time, not distance. The equation v = dx/dt implies that displacement is determined by integrating v over time. The user initially attempted to integrate with respect to x, leading to incorrect results. Properly applying the relationship between velocity, displacement, and time is crucial for accurate calculations. Understanding these fundamentals is essential for solving the problem correctly.
rudransh verma
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Homework Statement
A particle at x=0 at time t=0 starts moving along positive x axis with velocity v= alpha## \sqrt x##. Displacement of particle is
Relevant Equations
##v=\frac{dx}{dt}##.
Integration of v= integration of##(alpha \sqrt x)dx##.
But I am getting wrong answer.
 
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rudransh verma said:
Homework Statement:: A particle at x=0 at time t=0 starts moving along positive x-axis with velocity v= alpha## \sqrt x##. Displacement of particle is
Relevant Equations:: ##v=\frac{dx}{dt}##.

Integration of v= integration of##(alpha \sqrt x)dx##.
But I am getting wrong answer.
You have the wrong integral. Distance is the integral of velocity with respect to time, not with respect to distance.
 
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