Integration of velocity to get displacement

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SUMMARY

The discussion centers on the integration of velocity to determine displacement for a particle moving along the positive x-axis with a velocity defined as v = α√x. The user incorrectly attempts to integrate with respect to x instead of time, leading to an erroneous result. The correct approach involves using the relationship v = dx/dt, which necessitates integrating velocity with respect to time to find displacement.

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  • Understanding of basic calculus, specifically integration techniques.
  • Familiarity with the relationship between velocity, displacement, and time.
  • Knowledge of kinematic equations in physics.
  • Concept of variable substitution in integrals.
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  • Study the concept of integrating velocity with respect to time to find displacement.
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rudransh verma
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Homework Statement
A particle at x=0 at time t=0 starts moving along positive x axis with velocity v= alpha## \sqrt x##. Displacement of particle is
Relevant Equations
##v=\frac{dx}{dt}##.
Integration of v= integration of##(alpha \sqrt x)dx##.
But I am getting wrong answer.
 
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rudransh verma said:
Homework Statement:: A particle at x=0 at time t=0 starts moving along positive x-axis with velocity v= alpha## \sqrt x##. Displacement of particle is
Relevant Equations:: ##v=\frac{dx}{dt}##.

Integration of v= integration of##(alpha \sqrt x)dx##.
But I am getting wrong answer.
You have the wrong integral. Distance is the integral of velocity with respect to time, not with respect to distance.
 

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