1. The problem statement, all variables and given/known data Evaluate the integral: integral (-17e^x-36)/(e^(2x)+5e^x+6 dx 2. Relevant equations partial fractions 3. The attempt at a solution Basically, what i did was factored the bottom into (e^x+2) and (e^x+3) because when i expand that, it equals the bottom. From there, i set A/(e^x+2) + B/(e^x+3) and found that A is -15 and B=-2. As a result, the final answer i got was -15lnabs(e^x+3)-2lnabs(e^x+2)...However it's wrong. Apparently the answer is supposed to be -6x+log(2+e^x)+5log(3+e^x). Help Please!!