Integration Problem: Solve sin^3Φ from 0 to 2π

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SUMMARY

The integral of sin^3Φ from 0 to 2π can be solved using the substitution method. The expression sin^3Φ can be rewritten as (sin^2Φ)(sinΦ), which simplifies to (1 - cos^2Φ)(sinΦ) dΦ. This transformation allows for an effective substitution of variables, leading to the solution of the integral.

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ElDavidas
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It seems quite simple actually. But I'm still stuck:

[tex]\int_{0} ^ {2\Pi} sin^3\Phi d\Phi[/tex]

Can anyone help?
 
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That's a standard "sine or cosine to an odd power" integral.
[tex]sin^3\Phi d\Phi= (sin^2\Phi)(sin\Phi)d\Phi= (1- cos^2\Phi)(sin \Phi d\Phi)[/tex]
See any simple substitution you can use?
 

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