Integration Volume: Filling a Garden Pot to 45 cm Depth

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SUMMARY

The discussion focuses on calculating the volume of a garden pot filled to a depth of 45 cm using the mathematical model derived from the curve y=0.1x^2, rotated about the y-axis between x=10 and x=25. The volume is computed using the integral V=π∫[10 to 55] 10y dy, resulting in a volume of 14625π cm³, which equates to approximately 15π litres. The calculation is confirmed as correct by participants in the discussion.

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  • Understanding of integral calculus
  • Familiarity with volume calculations of solids of revolution
  • Knowledge of the properties of the curve y=0.1x^2
  • Basic understanding of unit conversions from cm³ to litres
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Homework Statement



A mathematical model for a large garden pot is obtained by rotating through 4 right angles about the y-axis the part of the curve y=0.1x^2 which is between x=10 and x=25 and then adding a flat base . Units are in cm . Garden compost is sold in litres . Find the number of litres required to fill the pot to a depth of 45 cm . (Ignore thickness of pot)

Homework Equations





The Attempt at a Solution



Fill up to the depth of 45 cm so i have to take the limits from 10 to 55.

so [tex]V=\pi \int^{55}_{10} 10 y dy[/tex]

=pi[5(55)^2-5(10)^2]

=14625 pi cm^3

=15 pi litres

Am i correct ?
 
Last edited:
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thereddevils said:
Fill up to the depth of 45 cm so i have to take the limits from 10 to 55.

so [tex]V=\pi \int^{55}_{10} 10 y dy[/tex]

=pi[5(55)^2-5(10)^2]

=14625 pi cm^3

=15 pi litres

Am i correct ?

Looks good! :smile:

(though I wouldn't leave the π in)
 
tiny-tim said:
Looks good! :smile:

(though I wouldn't leave the π in)

thanks !
 

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