Integration with Complex Numbers

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SUMMARY

The integral ∫^{∏}_{0}e^(1+i)x dx can be evaluated using the substitution u = (1+i)x, leading to the transformed integral ∫_0^{(1+i)π} e^u du. The correct approach involves adjusting the limits of integration to match the new variable. The real part of the integral evaluates to -(1+e^∏)/2, while the imaginary part evaluates to (1+e^∏)/2, confirming the solution's accuracy.

PREREQUISITES
  • Complex number theory
  • Integration techniques, specifically u-substitution
  • Understanding of exponential functions
  • Knowledge of limits of integration
NEXT STEPS
  • Study advanced integration techniques in calculus
  • Learn about the properties of complex exponentials
  • Explore the application of complex numbers in calculus
  • Investigate the use of substitution methods in definite integrals
USEFUL FOR

Students studying calculus, particularly those focusing on complex analysis and integration techniques. This discussion is beneficial for anyone looking to deepen their understanding of integrating functions involving complex numbers.

waealu
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Homework Statement



Evaluate ∫[itex]^{∏}_{0}[/itex]e(1+i)xdx

Homework Equations



I know that the Real part of this is -(1+e)/2 and the Imaginary part is (1+e)/2, but I can't get the right solution.

I tried using u-substitution to create something that looked like ∫[itex]^{∏}_{0}[/itex]((eu)/(1+i))du

but I don't think that's correct. How do I solve this? Thanks!
 
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waealu said:

Homework Statement



Evaluate ∫[itex]^{∏}_{0}[/itex]e(1+i)xdx

Homework Equations



I know that the Real part of this is -(1+e)/2 and the Imaginary part is (1+e)/2, but I can't get the right solution.

I tried using u-substitution to create something that looked like ∫[itex]^{∏}_{0}[/itex]((eu)/(1+i))du

but I don't think that's correct. How do I solve this? Thanks!

Your substitution is fine. Except the u limits aren't the same as the x limits. Just do the u integration and then change back to x.
 
Or, equivalently, change the limits of integration as you change the variable. You made the substitution u= (1+ i)x so that du= (1+ i)dx so that dx= du/(1+ i). If [itex]x= \pi[/itex] then [itex]u= (1+ i)\pi[/itex] and if x= 0, u= 0 so the integral becomes
[tex]\frac{1}{1+ i}\int_0^{(1+i)\pi} e^udu[/tex]
 

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