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Intensity of Double Slit Pattern

  1. May 3, 2009 #1
    1. The problem statement, all variables and given/known data
    Could anyone help me to explain how the intensity of the double Slit pattern works because i'm looking at the formula and i'm really confused...


    2. Relevant equations
    I=4Icos^2(phi/2)
    A=2Ecos(phi/2)


    3. The attempt at a solution
     
  2. jcsd
  3. May 3, 2009 #2

    dx

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    What specifically do you want explained? The formula is easy to derive geometrically using the phasor diagram. Or you can do it algebraically: since only the phase difference matters, let the complex amplitude from slit one be just A (a real number). Then the complex amplitude from slit two will be Ae. The sum is therefore A(1 + e) = A(1 + cosφ + isinφ), and the magnitude squared is A²(1 + cos²φ + 2cosφ + sin²φ) = A²(2 + 2cosφ) = 2A²(2cos²(φ/2)) = 4A²cos²(φ/2).
     
    Last edited: May 3, 2009
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