Intensity with distance of LED

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  • Thread starter Thread starter InnealtóirLeTeacht
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SUMMARY

The discussion focuses on calculating the intensity of an LED at varying distances using the formula I_data = It * (z / √(d² + z²)) * z^(-2), where It is the LED power set at 130mW. The user, Claude, encountered incorrect intensity values when using a distance of z=0.15m (15cm) from the LED to the grid. Additionally, Claude seeks guidance on how using a lens to reduce the half power angle of the LED would impact the calculations, particularly regarding the integration of irradiance over different pixels.

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InnealtóirLeTeacht
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Hi everyone,

I am trying to create a data file that contains the intensity of an LED at a particular distance. For each data segment, the distance from the centre point (red dot on my very amateur paint drawing) is d and the distance from the LED to this purple grid is z. So I calculated that the intensity at each point is:

(where power of LED is It=130mW to take an example)

I_data = It*\frac{z}{\sqrt{d^2 +z^2}}*z^(-2)

so I am just multiplying the intensity perpendicular to the grid by the cosine of the angle and the inverse of the distance squared.

The distance from the LED to the grid is around 15cm, so originally I had z=0.15, which gave me the wrong intensity values. So I am not sure what to try next, any help would be greatly appreciated!

As a side note, I would also like to use a lens to reduce the half power angle of the LED and I'm wondering how this would affect the code above.
 

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Have you accounted for the fact that different pixels subtend different solid angles with respect to the source? I suspect if you attempt to integrate the irradiance over each pixel you will find your answer.

Claude.
 

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