Interference of Two Waves (Interferometer)

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Homework Statement



The input signal to the interferometer shown in the picture below is given by:

$$E_{\text{in}}=\sqrt{P}\exp\left(j\omega_{0}t+\frac{jD(t)\pi}{2}+j\varphi_{p}(t)\right). \tag{1}$$

##P## is the power that is received. The delay present in one arm of the interferometer is ##T_b##.

2017_09_16_15_16_26.jpg


I want to calculate the intensity/optical power at the output of the interferometer.

Homework Equations



For two waves ##\sqrt{I_{1}}\exp(j\varphi_{1})## and ##\sqrt{I_{2}}\exp(j\varphi_{2})##, the resulting interference equation is:

$$I=I_{1}-I_{2}+2\sqrt{I_{1}I_{2}}\cos\varphi \tag{2}$$

where ##d## is the delay distance, and ##\varphi = \varphi_2 - \varphi_1##.

The Attempt at a Solution



So from the interference equation:

$$P_{\text{out}}=2P\left[1+\cos\left(\frac{2\pi d}{\lambda}\right)\right]=2P\left[1+\cos\left(\frac{2\pi cT_{b}f}{c}\right)\right]$$

$$=2P\left[1+\cos\left(2\pi T_{b}f\right)\right]=2P\left[1+\cos\left(T_{b}\omega\right)\right]. \tag{3}$$

Is this correct?

The context of this problem is in telecom. ##\omega_0## represents the carrier frequency, ##D(t)## is the actual data that has to be recovered. However ##D## is absent from (3) so I am thinking that my result is probably not correct. :confused:

Any explanation would be greatly appreciated.
 
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