Constructive/Destructive Interference of Two Glass Plates

In summary, when light passes through two different mediums with different refractive indices, the phase of the waves will shift. This shift is due to the difference in the distance the waves have traveled. constructive interference occurs when the phase difference is 2kπ, while destructive interference occurs when the phase difference is 2k-1λ.
  • #1
superspartan9
23
0

Homework Statement



"Light is incident from above two plates of glass separated on both ends by small wires of diameter d = .6um. Considering only interference between light reflected from the bottom surface of the upper plate and light reflected from the upper surface of the lower plate, state whether the following wavelengths give constructive or destructive interference: λ = (a) 600 nm (b) 800 nm (c) 343 nm.

Homework Equations



Phase = (2m + 1)*pi for destructive interference, Phase = mλ for constructive interference, Phase constructive = 0 + 2N*pi, Phase destructive = pi + 2N*pi

The Attempt at a Solution



Looking at this problem, I can tell that when the light goes through the first plate into the air pocket between the two plates, there will be no phase shift because the index of refraction decreases between the mediums. When the light hits the second plate, there will be a phase shift of pi (if I understand reflection right, my professor is really bad at explaining these things). Beyond this, I'm stuck...
 
Last edited:
Physics news on Phys.org
  • #2
The red ray in the picture reflects directly from the first interface and the other (the blue) ray travels 2D distance in the air layer and changes pi phase at the air-glass interface. How much does the phase of a wave change when traveling some distance in a medium of refractive index N? What is the phase difference between the blue and red rays?


ehild
 

Attachments

  • interference.JPG
    interference.JPG
    3.8 KB · Views: 704
  • #3
Phase doesn't change going through a single medium does it? It only shifts when it goes from a low N medium to a higher N medium, right? And I believe the phase difference would be Pi after reflecting off the second glass surface.
 
  • #4
superspartan9 said:
Phase doesn't change going through a single medium does it? It only shifts when it goes from a low N medium to a higher N medium, right? And I believe the phase difference would be Pi after reflecting off the second glass surface.

The phase is changing as a wave travels. For a sinusoidal light wave, (with angular frequency ω and wavelength λ) the electric field varies as E0sin(2π*N*s/λ - ωt) along its path s in a medium of refractive index N. The red and blue waves meet at the same place and time, but then and there the blue one have traveled across the air layer twice. So the path difference, s, is twice the layer thickness, d: s=2d, and this means a phase change 4π*N*d/λ with respect to the red ray. This is added to the phase change at the interface. So the total phase difference is δ=4π*N*d/λ+π. If δ=2kπ the interference is constructive, the resultant of the waves is maximum. If δ=(2k+1)π the interference is destructive. Eliminating π, the condition for constructive interference is 4Nd=(2k-1)λ and that for the destructive one is 4Nd=(2k)λ, where k is an integer.
You need to find out if the given wavelengths correspond to constructive or destructive interference.

ehild
 
  • #5
Ok, I think I'm starting to understand. The only thing I'm unsure about is the Δphase between the two pieces of glass, mainly how you know to multiply the Δpath = 2dn/λ by 2∏ to get the phase. Is the 2∏ a constant multiplier?

That aside, let me just clarify why things work like you've explained. The total path traveled is 2*d because the light travels through the medium, hits the opposite piece of glass (which reflects causing the ∏ shift seen in total phase change), and then travels back up through the top piece of glass to interfere with the wave.

The δ = 2∏k or 2∏k + ∏ comes from the fact that any odd multiplier of ∏ causes destructive and even ones cause constructive interference, correct?

Thank you so much for you help, by the way! :D
 
  • #6
2π is the same constant that appears in the angular frequency, ω=2ωf where f is the frequency.
A wave is periodic both space and time. The time period is T=1/f, and the period in space is the wavelength, λ. The sine or cosine functions are periodic with 2π. sin(ωt) is a periodic function of time, with period T=2π/ω.
sin((2π/λ)*s) is periodic in length s, with period of λ, the wavelength. If s=λ or 2λ or k*λ , the sine function has the same value. The wave Asin((2π/λ)*s-(2π/T)*t)is periodic both in time and in space. If s changes with integer multiple of λ or/and t changes with integer multiple of T, the wave stays the same.

It looks to me that you have understood this interference thing. :smile:

ehild
 

1. What is constructive interference?

Constructive interference refers to the phenomenon where two or more waves combine to produce a larger wave. In the case of two glass plates, this means that the light waves passing through the plates will combine to produce a brighter and more intense light.

2. How does constructive interference occur with two glass plates?

Constructive interference occurs when the peaks and troughs of the light waves passing through the two glass plates align with each other, resulting in a larger and more intense wave. This happens because the glass plates act as a medium for the light waves to pass through, and the distance between the plates determines the phase difference between the waves.

3. What is destructive interference?

Destructive interference is the opposite of constructive interference, where two or more waves combine to produce a smaller or even no wave at all. In the case of two glass plates, this means that the light waves passing through the plates will cancel each other out and result in a darker or even completely dark area.

4. How does destructive interference occur with two glass plates?

Destructive interference occurs when the peaks of one wave align with the troughs of another wave, resulting in a cancellation of the waves. This happens because the distance between the glass plates causes the waves to have a phase difference that leads to their cancellation instead of reinforcement.

5. What factors can affect constructive/destructive interference of two glass plates?

The distance between the two glass plates, the angle at which the light waves pass through the plates, and the wavelength of the light being used are all factors that can affect constructive and destructive interference. Additionally, the refractive index of the glass plates and any imperfections or impurities in the plates can also impact the interference patterns.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
840
Replies
5
Views
1K
Replies
54
Views
5K
Replies
4
Views
335
  • Introductory Physics Homework Help
Replies
3
Views
1K
Replies
3
Views
12K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Atomic and Condensed Matter
Replies
0
Views
1K
  • Advanced Physics Homework Help
Replies
2
Views
3K
Back
Top