Internal energy and thermal energy

Click For Summary
SUMMARY

The discussion centers on the definition of internal energy, represented by the equation Einternal = Etranslational + Evibrational + Erotational + Eother, where Eother includes chemical, magnetic, and electrostatic energy. Participants clarify that the translational energy referenced pertains to the random motion of individual molecules, which contributes to thermal energy, while ordered contributions relate to coordinated motions. The distinction between ordered and random contributions is critical for understanding thermal energy in gases, particularly in the context of kinetic theory. The discussion also highlights the inclusion of potential energy from molecular interactions in the total internal energy.

PREREQUISITES
  • Understanding of thermodynamics principles
  • Familiarity with kinetic theory of gases
  • Knowledge of energy types: translational, vibrational, rotational
  • Basic grasp of molecular interactions and potential energy
NEXT STEPS
  • Study the kinetic theory of gases in detail
  • Learn about the Boltzmann velocity distribution
  • Explore the relationship between internal energy and temperature
  • Investigate the role of potential energy in thermodynamic systems
USEFUL FOR

Students and educators in physics, particularly those focusing on thermodynamics and kinetic theory, as well as researchers interested in molecular energy contributions and thermal dynamics.

eprparadox
Messages
133
Reaction score
2
I'm watching a lecture introduction internal energy and in it, the lecturer states the following for some system:

E_{internal} = E_{translational} + E_{vibrational} + E_{rotational} + E_{other}

where ## E_{other} ## could be chemical energy, magnetic energy, electrostatic energy etc.

Then he circles ## E_{translational} + E_{vibrational} + E_{rotational} ## and states that the RANDOM portions of these energy contributions represents the thermal energy. He says there is an ordered contribution from these terms and an unordered contribution and that this unordered (or random) contribution is the thermal energy.

What does the ordered vs. random contributions mean? I have no idea what that means.
 
Science news on Phys.org
eprparadox said:
What does the ordered vs. random contributions mean? I have no idea what that means.
Me neither! Can you post a link to the lecture?

eprparadox said:
E_{internal} = E_{translational} + E_{vibrational} + E_{rotational} + E_{other}
This doesn't bode well. Translational energy is definitely not a form of internal energy.
 
I think it's talking about the motion of a body as a whole, i.e. the coordinated motion of the atoms that make it up. For example, if you throw a ball, the translational motion of the ball is not internal energy - if you throw it faster it is not hotter - but the random motions of the atoms (superimposed on their ordered motion with the ball) do constitute internal energy - if the ball is hotter these random motions are more energetic.
 
DrClaude said:
Translational energy is definitely not a form of internal energy.
Is he not referring to the translational Energy of the individual molecule within the gas? After all, in elementary kinetic theory of gases, that is the only form of internal energy that's considered. The Rotational Energy that is also in the expression would normally be assumed the molecular rotation and not the coordinated rotation of the whole.
We would need to see the lecture to get the exact context of the expression. @mjc123 and I have both managed to get totally opposite messages from this; that speaks volumes. :smile:
 
I support mjc123's description of this very standard development. An example is an ideal monatomic gas. If ##\mathbf{v_i}## is the velocity of the i'th atom, then the average velocity of the gas is $$\bar{\mathbf v}=\frac{\sum_1^N{\mathbf{v_i}}}{N}$$If ##\mathbf{v'_i}## represents the deviations from the average velocity, then $$\mathbf{v_i}=\bar{\mathbf{v}}+\mathbf{v'_i}$$The total energy of the gas is the sum of the kinetic energies its particles: $$E=\sum_1^N\frac{m}{2}(\bar{\mathbf{v}}+\mathbf{v'_i})^2=N\frac{m}{2}\bar{v}^2+\frac{m}{2}\sum_1^Nv_i^2$$where the square on the left hand side of this equation symbolically represents the dot product of the vector velocity with itself. The first term on the right hand side of this equation is the "coordinated" kinetic energy of the gas, and the second term is the "random" kinetic energy, also called the internal energy of the gas. Thus,
$$E=(KE)+U$$U is typically calculated from the Boltzmann velocity distribution.
 
  • Like
Likes   Reactions: Lord Jestocost
Hey all!

Here is the lecture:

I set it to start at 1:25 but it's over the first few minutes that he discusses this.

In terms of the translational component to the internal energy, I think he is referring to the individual motions of the particles, as seen in the center of mass and as noted by @sophiecentaur.

I'll take a look at what you wrote @Chestermiller and respond soon!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
685
  • · Replies 15 ·
Replies
15
Views
3K
Replies
12
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
19K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K