Internal resistance circuit problem

[Sarlizwx]

Homework Statement

In a circuit, two identical batteries with EMF of 22 V and internal resistance of 7 Ohm are placed in parallel to provide power to a load resistance of RL = 35 Ohms. What is the power transferred from the current to RL to heat the resistor?

Homework Equations

Is R(L) (Resistance load) mean the same thing as R(total)? I know EMF = Isys * Rsys as well.

The Attempt at a Solution

Only drew the diagram, labeled areas and put the RL = [1/R(1) + 1/R(2)] ^ -1I also know that Itot = I1 + I2. I'm assuming here that EMF of 22V is for each battery?

 

[Saketh]

The load resistance is the resistance of the resistor that is added to the circuit. In this case, the total resistance is not the same as the load resistance.

 

[Sarlizwx]

So RL = ((1/R1) + (1/R2))^-1 is an incorrect statement?

 

[GmL]

Your equation RL = ((1/R1) + (1/R2))^-1 only equates the total (internal) resistance of the batteries. The load resistance is a separate load (resistor) in the circuit which is in series with the two batteries. R(total)=(total internal resistance)+(load resistance RL).

 

[Fez07]

Circuit/Power

Howdy,
If I've got the right circuit in mind, you could use Thevenin's Theorem to find the thevenin equivalent circuit then determine I and P.

Peace out.

Fez07

 

[Fez07]

Circuit/Power

Me again,
Forget my last comment. I was thinking of the wrong circuit. Use Superposition.

 

[Sarlizwx]

Don't recognize either of those, Fez07

 

[Fez07]

Circuit/Power

Firstly, is this the circuit you have?