Interpreting Ambiguous HW Question on Curve Length and Surface Patch Domains

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I got this HW question made up by the professor that I find ambiguous. It says

Consider the curve [itex]\theta (t)=\pi/2-t[/itex], [itex]\phi(t)=\log \cot(\pi/4-t/2)[/itex] on the sphere [itex]r(\theta,\phi)=(\sin\theta \cos\phi,\sin\theta\sin\phi,cos\theta)[/itex]

Find the length of the curve btw the points t=pi/6 and pi/4


He did not specify domains for either the curve nor the "surface" r. On one hand, if we take r to be a surface patch, this requires that the (maximum) domain be [itex]0 < \theta < \pi[/itex], [itex]0 < \phi < 2\pi[/itex]. Anything bigger and the domain is not open or r is not injective. But this surface patch does not cover the whole sphere.

I could also consider two other surface patches of the form [itex]r_{2,3}(\theta,\phi)=(\sin\theta \cos\phi,\sin\theta\sin\phi,cos\theta)[/itex] with appropriate domains, that together with r above form an atlas for the unit sphere.

Any thoughts? How would you interpret this question?
 
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I don't know what you mean. The domain is pi/6<t<pi/4. From the above relations you can get r as a function of t, and this is just some curve.
 
There is another question after that:

Find the angles of intersection btw this curve and the parallels [itex]\theta = const.[/itex]

would you still say that the curve's domain is (pi/6,pi/4)? Or would you study it more carefully to find what is the maximum domain where the curve is defined and thus find all the possible intersectino points?
 
I would stick to (pi/6,pi/4), at least for this question. If you're curious, keep going, but then you're doing more than what's asked.