Intersection of Three events (probability)

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The discussion focuses on proving that the probability of the intersection of three events A, B, and C is at least equal to the sum of their individual probabilities minus two. The inclusion-exclusion principle is highlighted as a key method for this proof, emphasizing the importance of analyzing the areas in a Venn diagram. By labeling the areas of the Venn diagram according to how many times they are counted in the sum P(A) + P(B) + P(C), the '-2' accounts for double counting. This approach leads to the conclusion that the intersection probability is bounded as stated. Understanding this relationship is crucial for grasping the fundamentals of probability theory.
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Homework Statement


Show that for 3 events A, B, C, the probability P of the intersection of A, B, and C is greater than or equal to P(A) + P(B) + P(C) - 2.

aka: P(A intersection B intersection C) > or = P(A) + P(B) + P(C) - 2


Homework Equations


N/R


The Attempt at a Solution


Use venn diagram, look at areas of venn diagram in terms of complement
 
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What you need is inclusion-exclusion principle. It's as true for probability as for cardinality.
 
In terms of your Venn diagram, label each area by how many times it is counted in P(A)+P(B)+P(C). The '-2' then subtracts each area twice. What do you conclude?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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