Intersection of Three events (probability)

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SUMMARY

The discussion focuses on proving that for three events A, B, and C, the probability of their intersection, P(A ∩ B ∩ C), is greater than or equal to the sum of their individual probabilities minus two, expressed as P(A ∩ B ∩ C) ≥ P(A) + P(B) + P(C) - 2. The solution involves using a Venn diagram to visualize the areas representing the events and applying the inclusion-exclusion principle to account for overlaps. This method effectively demonstrates the relationship between the probabilities of the events and their intersection.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with Venn diagrams
  • Knowledge of the inclusion-exclusion principle
  • Ability to interpret probability notation
NEXT STEPS
  • Study the inclusion-exclusion principle in probability theory
  • Explore advanced applications of Venn diagrams in probability
  • Learn about conditional probability and its implications
  • Investigate the relationship between independent events and their probabilities
USEFUL FOR

Students studying probability theory, educators teaching probability concepts, and anyone interested in understanding the mathematical foundations of event intersections.

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Homework Statement


Show that for 3 events A, B, C, the probability P of the intersection of A, B, and C is greater than or equal to P(A) + P(B) + P(C) - 2.

aka: P(A intersection B intersection C) > or = P(A) + P(B) + P(C) - 2


Homework Equations


N/R


The Attempt at a Solution


Use venn diagram, look at areas of venn diagram in terms of complement
 
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What you need is inclusion-exclusion principle. It's as true for probability as for cardinality.
 
In terms of your Venn diagram, label each area by how many times it is counted in P(A)+P(B)+P(C). The '-2' then subtracts each area twice. What do you conclude?
 

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