I took a picture of a simple problem from my Diff Eq book. It is split up into two pictures for better resolution.(adsbygoogle = window.adsbygoogle || []).push({});

In summary,

ty'+2y=4t^2 (1)

Has the solutions,

y=t^2+C/t^2 (2)

So, equation (1) has infinite solutions of the form of (2). But imposing the initial condition, y(1)=2 constrains our solution to that of...

y=t^2+1/t^2 (3)

The natural domain of (3) is (-∞,0) U (0,+∞). So, over the previously specified domain, (3) is a solution to (1). However, in the book, and for other problems, it makes a habit of restricting the natural domain of the solution function. In this case it restricts the domain to (0,+∞) instead of (-∞,0) U (0,+∞). My question is, why is the domain of the solution restricted, when the entire domain satisfies both (1) and the initial value equation?

Thank you in advance!!!

--Darren

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Interval Restriction on Solutions to First Order Linear Equation

Loading...

Similar Threads - Interval Restriction Solutions | Date |
---|---|

I Interval of existence and uniqueness of a separable 1st ODE | Sep 28, 2016 |

What does it mean for a function to be defined on an interval? | May 11, 2014 |

Multigrid : Restriction operator | Nov 18, 2013 |

When y= a constant, how do you find the interval of definition? | Jan 27, 2013 |

Fourier Series Interval Points | Nov 24, 2012 |

**Physics Forums - The Fusion of Science and Community**