Intro Physics homework help - distance and velocity

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SUMMARY

The discussion centers on solving a physics problem related to distance and velocity using a velocity-time graph. The user initially calculated the area under the graph incorrectly, assuming a constant speed of 1.26 m/s over 3.4 seconds, which led to an incorrect answer of 3.97 meters. Another participant clarified the correct method for calculating the area under the velocity-time graph, enabling the user to identify their mistake and understand the correct approach.

PREREQUISITES
  • Understanding of basic physics concepts, particularly distance and velocity.
  • Familiarity with interpreting velocity-time graphs.
  • Knowledge of how to calculate the area under a curve.
  • Basic mathematical skills for performing calculations involving units of measurement.
NEXT STEPS
  • Study the principles of kinematics in physics.
  • Learn how to accurately calculate areas under curves in velocity-time graphs.
  • Explore examples of distance and velocity problems in introductory physics textbooks.
  • Practice solving various physics problems involving motion and graph interpretation.
USEFUL FOR

This discussion is beneficial for students studying physics, particularly those struggling with concepts of distance and velocity, as well as educators looking for effective ways to explain these topics.

mncyapntsi
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Homework Statement
An elevator going up from one floor to the next, where velocity is positive if it is upward. The acceleration at the start and the deceleration at the end are uniform and of the same magnitude. If the maximum speed of the elevator is 1.26 m/s and it takes a total of 3.40 s for the elevator to move between the floors, what is the distance between the floors if the time that the elevator maintains its top speed is 2.90 s?
Relevant Equations
v=d/t ; x = xo + vt
I have tried this problem over 4 times and keep getting the exact same answer, which is incorrect. Could someone please help by pointing out what I did wrong, or letting me know if I am actually on the completely wrong path?
Thanks!
Have a wonderful day :)
Screen Shot 2021-09-14 at 2.59.30 PM 1.png
 
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Is the answer supposed to be ##3.97m##?
 
PeroK said:
Is the answer supposed to be ##3.97m##?
Could I please ask how you got that?
 
mncyapntsi said:
Could I please ask how you got that?
I calculated the area of your velocity-time graph. Whereas, you calculated the area of a velocity-time graph for a speed of ##1.26 m/s## for the full ##3.4s##.
 
OH! I see what I did - thanks a lot!
 

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