Inverse hyperbolic function expressed as inverse trigonometry function

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  • Thread starter Happiness
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Main Question or Discussion Point

Consider ##y=\cos{-x}=\cos x=\cosh ix##.

Thus, ##\pm x=\cos^{-1}y## and ##ix=\cosh^{-1}y##.

So ##\cosh^{-1}y=\pm i\cos^{-1}y##.

Renaming the variable ##y##, we have ##\cosh^{-1}x=\pm i\cos^{-1}x##.

Next, we evaluate the derivative of ##\cosh^{-1}x## by converting it to ##\cos^{-1}x## using ##\cosh^{-1}x=i\cos^{-1}x##.

##\frac{d}{dx}\cosh^{-1}x=\frac{d}{dx}i\cos^{-1}x##
##=i\frac{-1}{\sqrt{1-x^2}}## --- (*)
##=\frac{-i}{i\sqrt{x^2-1}}## where I've used the rule ##\sqrt{-c}=i\sqrt{c}## for ##c>0##, since ##x>1##.
##=\frac{-1}{\sqrt{x^2-1}}##, which differs from the correct answer by a negative sign.

This means we would get the correct answer had we used ##\cosh^{-1}x=-i\cos^{-1}x##.

My question is how do we know when to add the negative sign.

I realized that step (*) is wrong because the formula for the derivative of ##\cos^{-1}## is true only for ##-1<x<1##. However, since we get the right answer in the end, it seems like there is a reason why we could still use the formula for values of ##x## outside ##-1<x<1##, and an explanation when we should use ##\cosh^{-1}x=-i\cos^{-1}x## instead of ##\cosh^{-1}x=i\cos^{-1}x##.
 

Answers and Replies

Buzz Bloom
Gold Member
2,076
356
Hi Happiness:

I am not sure I understand what you are asking, but it seems to me that the first equation omitted
cosh ix = cosh -ix.​
That is, both cos and cosh are symmetrical functions. Therefore when you take the inverse, you get two possible correct answers:
+ and -. This the same as taking the square root of a positive value and getting both a positive and negative result.

Hope this helps.

Regards,
Buzz
 
665
24
Hi Buzz

Thanks for replying.

I am asking why is ##\cosh^{-1}x=-i\cos^{-1}x##? And why isn't ##\cosh^{-1}x=+i\cos^{-1}x##? Why is the positive result rejected?
 
Buzz Bloom
Gold Member
2,076
356
Why is the positive result rejected?
Hi Happiness:

Can you post a link to where you found that the positive result is rejected?

Regards,
Buzz
 
665
24

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