Does Doubling y in an Inverse Proportion Problem Halve the Constant?

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In an inverse proportion problem where y is proportional to 1/x, doubling y leads to a question about the relationship with x. The discussion clarifies that if y ∝ 1/x, then 2y is proportional to 1/0.5x, not 1/2x. This is because the proportionality constant changes when y is doubled. The conclusion emphasizes that doubling y simply alters the constant in the inverse relationship. Understanding this relationship is crucial for solving inverse proportion problems effectively.
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Hello

if y \propto 1/x
would 2y \propto 1/0.5x
or 2y \propto 1/2x

thank you for any replies
 
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e44-72 said:
Hello

if y \propto 1/x
would 2y \propto 1/0.5x
or 2y \propto 1/2x

thank you for any replies

if y \propto 1/x then
y \propto 2y \propto 1/0.5x \propto 1/x \propto 1/2x
 
y ∝ 1/x means y = k/x for some constant k. For your question, it means simply change the constant.
 

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