Inverse Z transform - contour integration

[etf]

Hi!
Here is my task:
Find inverse z transform of $$X(z)=\frac{1}{2-3z}$$, if $$|z|>\frac{2}{3}$$ using definition formula.
I found that $$x(n)$$ is $$\frac{1}{3}(\frac{2}{3})^{n-1}u(n-1)$$ (using other method). But how can I find it using definition formula, $$x(n)=\frac{1}{2\pi j}\oint_{C}^{ } X(z)z^{n-1}dz$$ ?
Thanks in advance

 

[rude man]

Forget it, unless and until you have taken a course in functions of a complex variable with contour integration.
Sample: http://ocw.mit.edu/resources/res-6-008-digital-signal-processing-spring-2011/study-materials/MITRES_6_008S11_sol06.pdf

 

[SteamKing]

There is a similar integral technique for finding inverse Laplace transforms:

http://en.wikipedia.org/wiki/Inverse_Laplace_transform

No one uses it.

It's more practical to get your transform (Laplace or Z) into a form which can be looked up in a table.