- #1
Master1022
- 611
- 117
- Homework Statement
- Find an expression for the Z-transform of the following equation: [tex] x_{n + 1} = r x_{n} \left( 1 - x_{n} \right) [/tex]
- Relevant Equations
- z-transform
Hi,
I am trying to work out how I could obtain an expression for a z-transform for the following expression:
[tex] x_{n + 1} = r x_{n} \left( 1 - x_{n} \right) [/tex]
I am hoping to derive X(z) and then use the final value theorem to show agreement with numerically calculated steady state values.
I haven't made it very far because I don't know what to do with a convolution term I have in my z-transform.
Method:
Taking the Z-transform of both sides we get: (we will let [itex] \bar{X} = X(z) = Z \{ x_{n} \} [/itex])
[tex] z \bar{X} = r \bar{X} - r \bar{X} * \bar{X} [/tex]
How would I deal with the convolution term here without explicitly knowing an expression for [itex] \bar{X} [/itex]? Is it possible to proceed with this approach?
Thanks in advance for the help.
I am trying to work out how I could obtain an expression for a z-transform for the following expression:
[tex] x_{n + 1} = r x_{n} \left( 1 - x_{n} \right) [/tex]
I am hoping to derive X(z) and then use the final value theorem to show agreement with numerically calculated steady state values.
I haven't made it very far because I don't know what to do with a convolution term I have in my z-transform.
Method:
Taking the Z-transform of both sides we get: (we will let [itex] \bar{X} = X(z) = Z \{ x_{n} \} [/itex])
[tex] z \bar{X} = r \bar{X} - r \bar{X} * \bar{X} [/tex]
How would I deal with the convolution term here without explicitly knowing an expression for [itex] \bar{X} [/itex]? Is it possible to proceed with this approach?
Thanks in advance for the help.