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I have been doing an experiment at school looking into how the angle of a cone affects the time it takes for it to fall 2m. The data consistently shows an inverse relationship but it is unclear whether or not they are inversely proportional i.e. if the angle doubles, the time taken to fall halves. I wanted to see if I could relate the angle of the cone to the force of drag in some way and wanted to know if someone could help me?

The drag equation we are given is:

F

_{D}= C

_{D}Apv

^{2}(FD = force of drag, C

_{D}= drag coefficient, A = cross-sectional area, p = density of fluid, v = velocity)

From looking at the equation I am thinking that the angle of the cone will affect the cross sectional area. So I need some way of expressing the cross-sectional area in terms of the angle of the cone so I see what the relationship would be between the angle of cone and the force of drag. Any ideas?

Many thanks!