1. The problem statement, all variables and given/known data We're told to find the coefficient of friction for a mousetrap car that we've made, using values that we attained ourselves. We released the arm of the mousetrap onto a scale to find Fa → 1.0*10^2 Newtons. This is how we found Fa: m = 1.020kg (←mousetrap held back and hammer released onto scale, value recorded from scale) a = 9.8m/s/s (←factoring in gravity, which affects mousetrap's "release weight" on scale) Fa = ? Fa = ma = 1.020kg * 9.8m/s/s (Fg) = 9.996 Newtons = 10. Newtons (← rounded to correct amount of sig digs.) Using that, we solved for acceleration : Vi = 0.0m/s t = 1.56s (time to complete 3m) d = 3.0m a = ? d = Vi(t)+0.5a*(t^2) a = (3m)/(0.5)(1.56^2) a = 2.46 m/s/s = 2.5m/s/s (← rounded to correct amount of sig digs.) With that Ff and Fnet was solved for : Fa = 10. Newtons m = 0.128kg a = 2.5m/s/s Ff = ? Ff was needed later so rather than doing m*a to find Fnet, we found Ff first to find Fnet: Fnet = ma Fa + Ff = ma Ff = 0.128kg(2.5m/s/s)- 10. Newtons Ff = -9.68 Newtons = -9.7 Newtons (← rounded to correct amount of sig digs.) And now Fnet: Fnet = Fa-Ff = 10. Newtons - 9.7 N = 0.3 Newtons At this point, everything seemed reasonable, but then we needed to solve for the coefficient of friction. 2. Relevant equations μk = Fk/Fn 3. The attempt at a solution μk = Fk/Fn = -9.7 Newtons / (0.128)*(9.8) = 7.73 = 7.7 (← rounded to correct number if sig digs.) The question is, does 7.7 make sense for a coefficient of friction, and does everything else look sound?. The mousetrap car we made seemed to be of low friction , except between the ground and the wheel, where we wanted to maximize friction (balloons were used). Thanks.