Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3?

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Homework Help Overview

The discussion revolves around whether the set {a0 + a1x + a2x2 + a3x3 | a0a3 - a1a2 = 0} constitutes a subspace of the polynomial space P3. Participants are exploring the conditions necessary for a set to be classified as a subspace.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the necessary conditions for a set to be a subspace, including the presence of the zero polynomial and closure under addition and scalar multiplication. Questions arise about how the specific condition a0a3 - a1a2 = 0 affects these properties.

Discussion Status

There is an ongoing exploration of the implications of the defining equation for the set. Some participants suggest verifying the closure properties, while others consider the relationship between this polynomial set and vector spaces in R4 for potential insights.

Contextual Notes

Participants note that specific values for coefficients may not be suitable for demonstrating subspace properties unless the set is confirmed to be a subspace. The discussion includes considerations of how to approach the problem without directly providing a solution.

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Homework Statement


Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3? Why or why not?

*The digits should be in subscript.

How would I go about answering this?
 
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dmitriylm said:

Homework Statement


Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3? Why or why not?

*The digits should be in subscript.

How would I go about answering this?

Let's call your set as described above S. There are three things you need to verify to say that S is a subspace of P3:
  1. The zero polynomial is in S.
  2. If p1 and p2 are any two polynomials in S, then p1 + p2 is in S.
  3. If c is any real constant and p1 is in S, the cp1 is also in S.
 
Do I need to do anything with the conditions a0a3 – a1a2 = 0?
 
Absolutely! That equation describes the elements of your set.
 
How do I derive the elements of my set from the equation?

If I select a0=2, a1=3, a2=4, and a3=6, then these numbers meet the requirements of the equation.

Similarly, a0=-2, a1=-3, a2=-4 and a3=-6 would as well. Where do I go from there?
 
Last edited:
Unless the set is not a subspace and you can find some functions in the set that don't satisfy the subspace requirements, you won't be able to pick specific numbers for the coefficients.

Let p1(x) = a0 + a1x + a2x2 + a3x3 and p2(x) = b0 + b1x + b2x2 + b3x3, where both functions are in your set.

Is p1(x) + p2(x) also in the set?
Is k*p1(x) in the set for any constant k?
 
Thanks a lot for the help!
 
Mark44 said:
Let's call your set as described above S. There are three things you need to verify to say that S is a subspace of P3:
  1. The zero polynomial is in S.
  2. If p1 and p2 are any two polynomials in S, then p1 + p2 is in S.
  3. If c is any real constant and p1 is in S, the cp1 is also in S.

He doesn't need to show (1); this follows directly from (3).
 
The list can be shortened even more. All you really need to show is that cp1 + p2 is in the set for any constant c and any functions p1 and p2 in the set.
 
  • #10
dmitriylm said:

Homework Statement


Is {a0 + a1x + a2x^2 + a3x^3 | a0a3 - a1a2 = 0} a subspace of P3? Why or why not?

*The digits should be in subscript.

How would I go about answering this?

I think that it might just be the polynomial thing that is causing you troubles; is that accurate? If it is, could you prove that a set of vectors in R^n is a subspace of R^n. That is, what if I asked this:

Is {(a_0),(a_1),(a_2),(a_3) | a0a3 - a1a2 = 0} a subspace of R^4, could you solve it? If so, you might want to prove (or disprove) that this is a subspace of R^4, then you can literally just take your proof and translate it to P^3. Do you understand what I am saying? I'm saying that R^4 and P^3 are essentialy the same (that is, they are isomorphic.) You can't prove it in R^4 and turn this in, but you can use it to get some insights.
 

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