Is Common Mode When Identical Signals Are Applied to a Differential Amplifier?

  • Thread starter Thread starter smuscat
  • Start date Start date
Click For Summary
SUMMARY

A common-mode signal occurs when identical signals are applied to both inputs of a differential amplifier, while a differential-mode signal is applied oppositely between the two inputs. The discussion emphasizes the use of operational amplifiers (opamps) to filter out AC interference, such as a 50 Hz supply, from an ECG signal. The effectiveness of this filtering depends on the common-mode rejection ratio (CMRR) specified in the opamp's datasheet and the feedback configuration used. Proper input impedance balancing and understanding the input common-mode range are critical for optimal performance.

PREREQUISITES
  • Understanding of common-mode and differential-mode signals
  • Familiarity with operational amplifier (opamp) configurations
  • Knowledge of common-mode rejection ratio (CMRR)
  • Basic principles of filtering in electronic circuits
NEXT STEPS
  • Research the specifications of opamps, focusing on common-mode rejection ratio (CMRR)
  • Learn about instrumentation amplifier configurations for enhanced common-mode interference rejection
  • Study the concept of input common-mode range and its importance in opamp applications
  • Explore feedback configurations in opamps to optimize performance in filtering applications
USEFUL FOR

Electronics engineers, biomedical engineers, and anyone involved in designing circuits for signal processing, particularly in medical applications like ECG monitoring.

smuscat
Messages
31
Reaction score
0
Hi!

Please tell me if understand wrong.

Common mode ,is when the two same signals are applied to differential amplifier?


Thanks
 
Physics news on Phys.org
smuscat said:
Hi!

Please tell me if understand wrong.

Common mode ,is when the two same signals are applied to differential amplifier?


Thanks

That's pretty much correct. A common-mode signal is applied to both conductors together. A differential mode signal is applied between the two conductors, in a opposing fashion.

So if you have a transformer with a center-tapped secondary, you drive a differential signal through to the secondary by driving a signal into the primary, and you can drive a common-mode signal out the secondar with respect to ground by driving the center tap of the secondary with respect to ground.
 
I have the following situation.

An opamp is used to filter 50 hz supply from a patient to read a perfect ecg.

Attached you can find the opamp configuration.

The AC interference is connected to the opamp in the inverting input and non inverting as common mode and an ecg signal is applied between the inputs of the opamp.

My questions are the following.

Is the AC interfernce signal is eleminated by the opamp? I think Because it has the property to amplfie the difference between the two inputs in other worlds cancel out because they are of the same magnitude and phase difference.

Will the opamp finally feature the ecg signal only on the output? I think yes.

Please tell if gone wrong and please answer me in simple worlds.

Thanks
 

Attachments

  • Scan0006.JPG
    Scan0006.JPG
    18.6 KB · Views: 476
The CM rejection you get will depend on the capabilities of the opamp. Look in the opamp datasheet to see what kind of CM rejection it advertises.

But in general, yes, that is what you are using the differential amplifier characteristics of the Opamp to do.

However, a couple comments about the sketches. First, you do not use an Opamp in open loop configuration, so the diagram on the right should show the full amp circuit with feedback. The CM rejection you get also depends on the feedback configuration, and how balanced an input impedance you present to the input signals. Look up instrumentation amplifier configurations of Opamps to see how to best reject CM interference.

Finally, the drawing on the right is not drawn well. It should show capacitive coupling of the CM interfering signal to both inputs on the opamp (via two separate capacitances), not just a coupling to one side (with and implied low-impedance tie via the differential signal source, which is not always the case).
 
smuscat said:
I have the following situation.

An opamp is used to filter 50 hz supply from a patient to read a perfect ecg.

Attached you can find the opamp configuration.

The AC interference is connected to the opamp in the inverting input and non inverting as common mode and an ecg signal is applied between the inputs of the opamp.

My questions are the following.

Is the AC interfernce signal is eleminated by the opamp? I think Because it has the property to amplfie the difference between the two inputs in other worlds cancel out because they are of the same magnitude and phase difference.

Will the opamp finally feature the ecg signal only on the output? I think yes.

Please tell if gone wrong and please answer me in simple worlds.

Thanks

You are right what you wrote.

Sorry for my luck of theory but I only need a confermation what I wrote.
Thanks Berkeman
 
smuscat said:
Sorry for my luck of theory but I only need a confermation what I wrote.
Thanks Berkeman

No worries. BTW, I forgot to mention one other thing. You should look for the "input common mode range" specification of the opamp that you are intending to use in this project (or in this problem). Can you tell us why it might be important not to exceed that input voltage range?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
3K
Replies
1
Views
2K
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K